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201711-12-Q6
A hot-air balloon is moving vertically upwards with a constant speed of $3.00\ \mathrm{m s^{-1}}$. A sandbag is dropped from the balloon. It takes 5.00 s for the sandbag to fall to the ground.
What was the height of the balloon when the sandbag was released?
一个热气球以3.00米每秒的恒定速度垂直向上移动。 沙袋从气球上掉下来。 沙袋跌落到地面需要5.00秒。
释放沙袋时气球的高度是多少?
答案:
分析Analysis
Assume downward as positive direction, then initial speed is $-3.00\ \mathrm{m s^{-1}}$
假设向下为正方向,那么初始速度为 $-3.00\ \mathrm{m s^{-1}}$
constant accelerate at $g$, initial speed $u$ is given, also know $t$, thus know 3 variables out of 5 ($u$, $v$, $t$, $a$, $d$), we can use the formula $h = ut + \frac{1}{2}at^2$
匀加速运动$g$, 已知初始速度$u$, 已知$t$, 可以用5公式求出$h$
$$
h = -3 \times 5 + \frac{1}{2}g \times 5^2 = 107.625\ \mathrm{m}
$$
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